Easiest Subnetting : Even 5 Years Old Can Do This

Hello, This is my first english article, Just give me a momment to translated it from google. Oke, i just want to review about ip subnet. As much as i know, subnetting is simple but almost engineer in entry level are strugling with that. So, let i tell you this tricky secret :

1. First, tell to your brain
    /24 is C Class
    /16 is B Class
    /8 is A Class

 2. Basicly, this subnetting methode is come from Ip address Class C which comes from multiple of 8
    /24 = 256 address per subnet, start from 0
    /25 = 128 half of 256
    /26 = 64
    /27 = 32 
    /28 = 16 half of 32
    /29 = 8
    /30 = 4
    /31 = 2 half of 4, and so on
    /32 = 1
   Just remember the underlined numbers 256,32,4.

3. Now start implementing this case
  
    CLASS C
    10.10.10.10.10/29
    The nearest number from /29 is /30 (which i told you to remember). So the Question is ?

    IP address persubnets = 8 (the nearest number you've remembered, divided or multipled it by 2)
    Network address = 10.10.10.8 (10.10.10.10 is included in range 8-15, the first is network)
                                    0-7

                                    8-15

                                    16-31

                                    and so on, untill 255

    Broadcast address = 10.10.10.15 (10.10.10.10 is included in range 8-15, the last is broadcast)

                                    0-7
                                    8-15
                                    16-31
                                    and so on, untill 255
    Host = 10.10.10.9 - 10.10.10.14
                Cause in range 8-15, the first is network and the last is broadcast.
                The number left will be host address, and could be use as your ip device.
    Subnet = 248 (256 - 8)
                   256 is amount of ip address in class c
                   8 is ip address per subnet.

    CLASS B
    30.30.30.30/23
    there is no nearest number. What should i do? easy man, i got it.
    How /23 could be as CLASS C ? just do this 23+8 = 31 which mean /31 = 2
    Where the 8 come from ? +8 is mandatory, the methode.
    So, what should i do with 2 ? ok this is the deal
    Ip address per subnets = 512
                                          2 x 256 (number of ip address in class c), got it?
    Network address = 30.30.30.0
    Broadcast address = 30.30.31.255
                                      Cause the ip address per subnet is 512
                                      You have to jump from 30.30.30.0 to 30.30.31.0
                                      Which mean all ip address in range 30.30.30.0 - 30.30.31.255 is included
    Host = 30.30.30.1 - 30.30.30.254
    Subnet = 255.255.255.254.0
                   254 is 256-2 Remember 2 ? Thats the clue, noted that.
   
    CLASS A
    50.50.50.50/14
    Make /14 as class. What should you do? 14+8= 22, thats not enough. 22+8 = 30. /30 = 4
    Ip address = 262144
                         4 x 65536
                         65536 is the amount of ip address in class B (256 x 256 ip addres ip class c)
    Network = 50.48.0.0
                      50 is on range 48-51
    Broadcast = 50.51.255.255
    Host = 50.48.0.1 - 50.51.255.255
    Subnet = 255.252.0.0
                   252 is from 256 - 4

So, with your hard work, you could do those thing even better. Good luck!